What is the probability of getting a sum of 15 when two dice are thrown?
So, the number of favourable outcomes =1+2+4+6+2=15. We know that the number of possible outcomes is 36. Thus, the probability of getting the sum of two numbers as prime numbers is =1536=512. (b) We will now calculate the probability of occurrence of a doublet of an even number.
How many ways can a sum of 15 be obtained with 3 dice?
It is by finding non-negative integral solutions to the following equation. Therefore, the number of ways in which the sum of the numbers observed in 3 rolls of fair dice is 15 is equal to 10.
What is the probability of rolling a sum of 4?
Probabilities for the two dice
|Total||Number of combinations||Probability|
What is the probability of getting 1 and 5 If a dice is thrown once?
So they are mutually exclusive events, therefore their probabilities add to 1. By symmetry we expect that each face is equally likely to appear and so each has probability = 1/6. The outcome of a 5 is one of those events and so has probability = 1/6 of appearing.
What is the probability of getting a sum as 3 If a dice is thrown * 1 point?
probability of getting sum as 3 = 1/18
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How many ways can a sum of 16 be obtained?
Now count all the squares which contain 16 and it should be six of them. Therefore the probability of getting a total of 16 will be 6/216 or 1/36. The set of all possibilities for three six- sided dice numbered 1–6 is 216 . P(16) = # ways to get 16 / set of all possibilities.
How many ways can first and second place be awarded to 10 people?
For each of 10, there are 9. For each of those, there are 8. So we end up with Robert’s simple calculation of 10 x 9 x 8 = 720 ways.